# If the length of a 53 cm spring increases to 87 cm when a 1 kg weight is hanging from it, what is the spring's constant?

Jul 21, 2017

28.8 N/m

#### Explanation:

Δx = 87cm - 53cm

Δx = 34cm

$F = m g$

$F = 1 k g \cdot 9.8 \frac{m}{s} ^ 2$

$F = 9.8 N$

F = k * Δx

k = F / (Δx)

$k = \frac{9.8 N}{34 c m}$

$k = 0.288 \frac{N}{c m}$

$k = 28.8 \frac{N}{m}$