If the position of aparticle is given by x=5.0-9.8t+6.4t^2, what is the velocity and acceleration of the particle at t=4.0s?
The given equation can be compared with
which is an equation of position-time relationship of a particle moving with constant acceleration.
So,rearranging the given equation,we get,
So,the acceleration of the particle is constant i.e
Now,we can use the equation,