# If the speed of light is 3x10^8, determine the distance it takes in 1 light year. Report your results in km and in m. ????

Jun 20, 2018

Well...${c}_{\text{the speed of light}} = 3.0 \times {10}^{8} \cdot m \cdot {s}^{-} 1$...

#### Explanation:

And so we multiply this BY ONE year to get the distance travelled:

$3.0 \times {10}^{8} \cdot \cancel{m \cdot {s}^{-} 1} \times 1 \cdot {\cancel{\text{year"xx365*cancel"days"*cancel"year}}}^{-} 1$

$\times 24 \cdot \cancel{{\text{hours"*"day}}^{-} 1}$

$\times 60 \cdot \cancel{{\text{minutes"*"hour}}^{-} 1}$

$\times 60 \cdot \cancel{{\text{seconds"*"minute}}^{-} 1}$

$\equiv 9.5 \times {10}^{15} \cdot m$... ugh arithmetic...

And you can report the distance in $\text{kilometres}$. How?