If the temperature of 34.4 g of ethanol increases from 25 °C to 78.8 °C, how much heat has been absorbed by the ethanol? The specific heat of ethanol is 2.44 J/(gC)?

1 Answer
Jun 6, 2017

Answer:

The ethanol has absorbed #"4500 J"#.

Explanation:

Use the following formula:

#q=mcDeltat#,

where #q# is energy in Joules, #m# is mass, #c# is specific heat capacity, and #Deltat# is change in temperature: #Deltat=(T_"final"-T_"initial")#

Organize your data:

Known

#m="34.4 g"#

#c=("2.44 J")/("g"*"C"^@")#

#T_"initial"="25"^@"C"#

#T_"final"="78.8"^@"C"#

#Deltat=78.8^@"C"-25^@"C"="54"^@"C"#

Unknown

#q#

Insert you data into the formula and solve.

#q=(34.4color(red)cancel(color(black)("g")))xx((2.44"J")/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C"))))xx(54^@color(red)cancel(color(black)("C")))="4500 J"# (rounded to two significant figures)