Question

If the theoretical yield of a reaction is 26.0 grams and you actually recovered 22.0 grams, what is the percent yield?

Answer 1

As always....`%"yield"="actual mass of stuff recovered"/"mass of stuff you should have got"xx100%`

Explanation:

Now of course, you have to identify the limiting reagent, and assess given masses, and actual yields.

But here we got `(22*g_"mass of stuff you got")/(26*g_"mass of stuff you should have got")xx100%`

`-=85%`