If the unequal angle in an isosceles triangle is 38, what is the measure of one of the base angles?

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Answer 1 · 2018-02-02T10:21:36

#71^@#

#"the sum of the angles in a triangle "=180^@#

#"the equal base angles sum "=180-38=142^@#

#rArr"base angle "=142/2=71^@#

Answer 2 · 2018-02-02T10:25:52

Base angles are #color(green)(71^0)# each

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Total Angle of a triangle = #180^0#

Given# /_A = 38^0, /_B = /_C# since it's an isosceles triangle.

#/_A + /_B + /_C = 180#

#:. 38 + (2 * /_B) = 180#

#2 * /_B = 180 - 38 = 142#

#/_B = 148 / 2= 71^0#

Therefore the base angles are #color(green)(71^0# each