If two inductors are joined in parallel their equivalent inductance is 2.4 if joined in series then equivalent inductance is 10 what is their difference?

Question

3675 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-26T18:42:56

Their difference is #=2#

Let the inductors be #L_1# and #L_2#

When the are in series

#L_1+L_2=10#

When they are in parallel

#1/L_1+1/L_2=1/2.4#

Therefore,

#(L_1+L_2)/(L_1L_2)=1/2.4#

#L_1L_2=2.4*10=24#

#(L_1+L_2)^2-4L_1L_2=100-4*24=4#

#L_1^2+L_2^2-2L_1L_2=4#

#(L_1-L_2)^2=4#

#L_1-L_2=sqrt(4)=2#