Question

If velocity is 0 and acceleration was set to m/s^2, then the distance is _____ meters after 2 seconds and ________ meters after 3 seconds?

Answer 1

So,as you have given the value of acceleration,now we can proceed with this problem.

Clearly,the object is moving with constant acceleration of `1ms^-2`, so to find distance(`s`) covered in given time(`t`),by using the equation, `s= ut + 1/2 a t^2` (considering for straight line motion,so that distance covered = displacement)

Here,the object started from rest, so `u=0`

And, given `a=1 m/s^2`

So,after `2 s` distance covered is `1/2×1×(2)^2=2 m`

And,distance covered after `3s` is `1/2×1×(3)^2 = 9/2 m`