If we have 16 gm of Oxygen gas at 273 C and 1 atm pressure, what would be its volume?

1 Answer
Jun 11, 2016

Answer:

The same as the volume of its container.

Explanation:

However, if you had such a quantity of gas in a piston, it would occupy a volume of approx. #11.2# #L#.

How do I know this? The molar volume of an ideal gas is #22,4*L*mol^-1# at #1# #atm# pressure and #T=273*K#. Oxygen, #O_2#, is a diatomic gas (most of the elemental gases, save for the Noble Gases, are diatomic).

We thus have #(16*g)/(32.0*g*mol^-1)# #=# #0.50*mol#

And using the molar volume of an Ideal Gas at standard pressure, #V=0.5*molxx22.4*L*mol^-1=?L# .