Question

If we have 16 gm of Oxygen gas at 273 C and 1 atm pressure, what would be its volume?

Answer 1

The same as the volume of its container.

Explanation:

However, if you had such a quantity of gas in a piston, it would occupy a volume of approx. `11.2` `L`.

How do I know this? The molar volume of an ideal gas is `22,4*L*mol^-1` at `1` `atm` pressure and `T=273*K`. Oxygen, `O_2`, is a diatomic gas (most of the elemental gases, save for the Noble Gases, are diatomic).

We thus have `(16*g)/(32.0*g*mol^-1)` `=` `0.50*mol`

And using the molar volume of an Ideal Gas at standard pressure, `V=0.5*molxx22.4*L*mol^-1=?L` .