# If we have 16 gm of Oxygen gas at 273 C and 1 atm pressure, what would be its volume?

Jun 11, 2016

The same as the volume of its container.

#### Explanation:

However, if you had such a quantity of gas in a piston, it would occupy a volume of approx. $11.2$ $L$.

How do I know this? The molar volume of an ideal gas is $22 , 4 \cdot L \cdot m o {l}^{-} 1$ at $1$ $a t m$ pressure and $T = 273 \cdot K$. Oxygen, ${O}_{2}$, is a diatomic gas (most of the elemental gases, save for the Noble Gases, are diatomic).

We thus have $\frac{16 \cdot g}{32.0 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.50 \cdot m o l$

And using the molar volume of an Ideal Gas at standard pressure, V=0.5*molxx22.4*L*mol^-1=?L .