# If x varies inversely with y and x = 8 when y = 6, how do you find y when x = 1?

Mar 3, 2018

$y = 48$

#### Explanation:

$x$ is inversely proportionate to $y$ can be written as:

$x \propto \frac{1}{y}$ -> $x = \frac{k}{y}$

Where $k$ is just an ungiven value that we need to figure out..

Inputting values given:

$8 = \frac{k}{6}$

$\therefore$ $k = 8 \times 6 = 48$

This is therefore written as:

$x = \frac{48}{y}$

Therefore when $y = 1$, using our little formula for this...

$1 = \frac{48}{y}$

Multiplying by $y$ solves this as it would cancel out the divide, giving us:

$y = 48$