If x:y = 2:3 and y:z = 3:4 find x:y:z ?

Question

9078 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-21T07:25:25

#" "x" ":" "y" ":" "z#

#" "2" ":" "3" ":" "4#

Luckily in this case, #y# represents #3# parts in each case.

#" "x" ":" "y#
#color(white)(www.w.ww)y" ":" "z#

#" "2" ":" "3#
#color(white)(wwwww.ww)3" ":" "4#

#" "x" ":" "y" ":" "z#

#" "2" ":" "3" ":" "4#

[In a situation where the ratios for #y# are different, you would have to find the LCM and increase each ratio accordingly.]

Answer 2 · 2018-02-21T07:25:38

# x:y:z=2:3:4#.

# x:y=2:3 rArr x/y=2/3 rArr x/2=y/3=lambda, say#.

Then, #x=2lambda, y=3lambda...........................................(star1)#.

Similarly, #y:z=3:4 rArr y=3mu, z=4mu................(star2)#.

#(star1) and (star2) rArr y=3lambda=3mu :. lambda=mu..........(star3)#.

Utilising #(star3)# in #(star 1)and (star2)#, we get,

#x=2mu, y=3mu, z=4mu," giving, "x:y:z=2:3:4#.