# If #y = 1/(1+x^2)#, what are the points of inflection of the graph f (x)?

##### 1 Answer

Nov 6, 2015

#### Explanation:

The inflection points are the zeroes of the second derivative. So, first of all, we need to compute it:

So, we need to find the zeroes of this function, which are the zeroes of its numerator: