# If y=9.2 when x=6, how do you find x when y=3 given that y varies inversely as x?

$x = 18.4$
$y \propto \frac{1}{x} \mathmr{and} y = k \cdot \frac{1}{x} \mathmr{and} y \cdot x = k \mathmr{and} 9.2 \cdot 6 = k \mathmr{and} k = 55.2 \mathmr{and} y \cdot x = 55.2$[k is constant for inversely variation equation ]
 y=3 ; x = ? y*x=55.2 or 3*x=55.2 or x = 55.2/3 = 18.4 [Ans]