If Y varies inversely as twice x and when x = 3, y = 8 how do you find y when x = 2?

2 Answers
May 29, 2017

Answer:

When #x=2, y = 12#

Explanation:

  • Write the statement as an inverse proportion first:
    #y prop 1/(2x)#
  • Change to an equation using a constant #k#

#y = k/(2x)," "# which can be written as #" "k = 2x xx y#

  • Use the values given to find a value for #k#
    #k = (2xx3) xx8 = 48#

  • Use the values for #k and x# to find #y#.

#y = k/(2x) = 48/(2xx2)#

# = 48/4 = 12#

May 29, 2017

Answer:

y = 12

Explanation:

Here #y prop 1/(2x)#

or, #y = k. 1/(2x)# ..............(i)

put x = 3 & y = 8 we get, #8 = k. 1/(2xx3)#

#rArr k = 48#

Again putting the value of k & x in (i) to find 'y'

#rArr y = 48. 1/(2xx2)#

#rArr y = 12#