# If y varies inversely as x and y=2 when x=6, how do you find y when x=36?

$y = \frac{k}{x}$
$2 = \frac{k}{6} \implies k = 12$
For x=36 we have $y = \frac{k}{36} = \frac{12}{36} = \frac{1}{3}$