# If y varies inversely as x and y=2 when x=6, how do you find y when x=36?

If y varies inversely as x then there is constant k such as

$y = \frac{k}{x}$

Hence for y=2 we have x=6 then

$2 = \frac{k}{6} \implies k = 12$

For x=36 we have $y = \frac{k}{36} = \frac{12}{36} = \frac{1}{3}$