# If y varies inversely with x, and x = 2.2 when y = 33. How do you find the inverse variation equation and use it to find the value of y when x = 4.84?

Aug 12, 2016

$\left(1\right) :$ Inverse Variation Eqn is, $x y = 72.6$.

$\left(2\right)$ : y=15#.

#### Explanation:

Given that, $y \propto \frac{1}{x} \Rightarrow x y = k =$const. of variation$\ne 0$.

To determine $k$, we use the data$: w h e n x = 2.2 , y = 33$

$\therefore \left(2.2\right) \left(33\right) = k = 72.6 \Rightarrow x y = 72.6 \ldots . . \left(1\right)$ is the reqd. eqn.

Now to find $y$, when $x = 4.84$, we use $\left(1\right)$ :

$4.84 y = 72.6 \Rightarrow y = \frac{72.6}{4.84} = 15$.