If #y=x + sqrt(a^2 + x^2)# where a is a constant, prove that #(a^2 + x^2)(d^2y)/(dx^2) + xdy/dx - y = 0#?

1 Answer
Apr 24, 2018

Please see below.

Explanation:

Here,

#y=x+sqrt(x^2+a^2)...tocolor(red)((A))#

Diff. w.r.t. #x#,we get

#(dy)/(dx)=1+1/(2sqrt(x^2+a^2))xx2x#

#=>(dy)/(dx)=1+x/sqrt(x^2+a^2)#

#"Multiplying both sides by "# #color(orange) sqrt(x^2+a^2)#

#=>sqrt(x^2+a^2)(dy)/(dx)=sqrt(x^2+a^2)+x...tocolor(red)([Use (A)]#

#=>sqrt(x^2+a^2)(dy)/(dx)=y ...tocolor(violet)((B)#

Again diff. w. r. t. #x#, #"using "color(blue)" Product Rule"#

#sqrt(x^2+a^2) (d^2y)/(dx^2)+ (dy)/(dx)*1/(2sqrt(x^2+a^2))xx2x=(dy)/(dx)#

#"Multiplying both sides by "# #color(orange) sqrt(x^2+a^2)#

#(x^2+a^2)(d^2y)/(dx^2)+(dy)/(dx)xxx=sqrt(x^2+a^2) (dy)/(dx)...tocolor(violet)([Use(B)]#

#(x^2+a^2)(d^2y)/(dx^2)+x(dy)/(dx)=y#

#(x^2+a^2)(d^2y)/(dx^2)+x(dy)/(dx)-y=0#