If you add 25 ml. of 2.25 M NaOH to 500 ml. deionized water, what is the molarity of this solution?

1 Answer
anor277
Mar 19, 2018

We use the expression...#"molarity"="moles of solute"/"volume of solution"#

Explanation:

And so...we got...

#[NaOH]=(25xx10^-3*Lxx2.25*mol*L^-1)/(525xx10^-3*L)=0.107*mol*L^-1#....

Why did I quote a volume of #525*mL#? The question specified #500*mL# of distilled water?

I make the #pOH=0.97#...what is #pH#?

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