If you have a gas with an initial pressure of 5 atm and it occupies a volume of 10L. If you increase the volume to 13L, what will the new pressure of the gas be?

Feb 26, 2018

$\text{4 L}$

Explanation:

Use Boyle's Law

$\text{pressure(1)" xx "volume(1)" = "pressure(2)" xx "volume(2)}$

where

• $\text{pressure(1) = 5 atm}$
• $\text{volume(1) = 10 L}$
• $\text{pressure(2)" = "13 atm}$

Therefore

$\text{5 atm" xx "10 L" ="13 atm" xx "volume(2)}$

$\text{volume(2)" = ("5 atm" xx "10 L")/"13 atm" = "3.85 L" = "4 L} \to$ one sigfig