If you have a gas with an initial pressure of 5 atm and it occupies a volume of 10L. If you increase the volume to 13L, what will the new pressure of the gas be?

1 Answer
Feb 26, 2018

Answer:

#"4 L"#

Explanation:

Use Boyle's Law

#"pressure(1)" xx "volume(1)" = "pressure(2)" xx "volume(2)"#

where

  • #"pressure(1) = 5 atm"#
  • #"volume(1) = 10 L"#
  • #"pressure(2)" = "13 atm"#

Therefore

#"5 atm" xx "10 L" ="13 atm" xx "volume(2)"#

#"volume(2)" = ("5 atm" xx "10 L")/"13 atm" = "3.85 L" = "4 L" -># one sigfig