# If you roll a fair die three times, what is the probability that you don't roll any 5's?

Pr{ One does not roll any '5' in three consecutive rolls of a die} = ${\left(\frac{5}{6}\right)}^{3}$ = 125/216.
Here the events of throwing a number other than '5' in consecutive throws is independent. Hence probability is product of the probabilities namely (5/6) $\times$ (5/6)$\times$ (5/6) = 125/216.