If you roll two dice, what is the probability of rolling a 6 and a number greater than 4?

Mar 4, 2017

$\frac{1}{18}$

Explanation:

Since these two events are independent we can use the equation

$P \left(A \cup B\right) = P \left(A\right) \times P \left(B\right)$

$\text{Let "A="probability of rolling a 6 on one die}$

$\therefore P \left(A\right) = \frac{1}{6}$

$\text{ Let "B="probability of rolling a number greater that 4}$

$P \left(B\right) = \frac{\text{numbers greater than 4}}{6} = \frac{2}{6} = \frac{1}{3}$

$\therefore P \left(A \cup B\right) = \frac{1}{6} \times \frac{1}{3} = \frac{1}{18}$