If your sample of carbon dioxide contains #1.505 xx 10^(23)# how many grams of CO2 are present in the sample?

1 Answer
Apr 7, 2018

#"11 g"#

Explanation:

#"1 mol" = 6.022 × 10^23\ "molecules"#

Moles of #"CO"_2# present in sample

#1.505 × cancel(10^23\ "molecules") × "1 mol"/(6.022 × cancel(10^23\ "molecules")) = "0.25 mol"#

# #

Molar mass of #"CO"_2# is #"44 g/mol"#. Mass of #"0.25 mol"# of #"CO"_2# is

#0.25 cancel"mol" × 44\ "g"/cancel"mol" = "11 g"#