If zw is expressed in polar form what are r and theta ?
1 Answer
Mar 12, 2018
Explanation:
#"Given "z_1=r_1(costheta_1+isintheta_1)" and "#
#color(white)("Given ")z_2=r_2(costheta_2+isintheta_2)" then"#
#z_1z_2=r_1r_2[cos(theta_1+theta_2)+isin(theta_1+theta_2)]#
#"for "z=3(cos((3pi)/8)+isin((3pi)/8))" and "#
#color(white)("for ")w=6(cos((3pi)/4)+isin((3pi)/4))#
#rArrzw=(3xx6)[cos((3pi)/8+(3pi)/4)+isin((3pi)/8+(3pi)/4)]#
#color(white)(xxxx)=18(cos((9pi)/8)+isin((9pi)/8))#
#rArrr=18" and "theta=(9pi)/8#