# Immediate. Immediate. Please help with limit problem?

##### 3 Answers

Mar 31, 2018

#### Answer:

#### Explanation:

We want to solve

#lim_(x->0)(e^x-e^-x)/x#

This leads to an indeterminate form

therefore we can apply L'Hôpital's rule

#color(blue)(lim_(x->a)f(x)/g(x)=lim_(x->a)(f'(x))/(g'(x))#

Thus

#lim_(x->0)(e^x-e^-x)/x=lim_(x->0)(e^x+e^-x)/1=2#

Mar 31, 2018

#### Answer:

#### Explanation:

and

then

then

Apr 1, 2018

#### Answer:

Image....

#### Explanation:

Without L Hospital rule...