Question

In a 0.15m solution of Fe(no3)3, what is the concentration of nitrate ions?

Answer 1

Would it not be `3xx0.15*mol*kg^-1`?

Explanation:

In aqueous solution, ferric nitrate speciates to give FOUR ions...

`Fe(NO_3)_3(s) stackrel(H_2O)rarrFe^(3+) + 3NO_3^(-)`..

And so `[NO_3^(-)]=0.45*mol*kg^-1`..