Question

In a 2.5 M `CaCl_2` solution, what is the molarity of the calcium ions?

Answer 1

AS the name says on the tin, the molarity of calcium ion is `2.5*mol*L^-1`....

Explanation:

And in one litre of solution there are `1*Lxx2.5*mol*L^-1xx6.022xx10^23*mol^-1` individual calcium ions.....What is the concentration of chloride ions?

Answer 2

`2.5M`

Explanation:

Molarity is defined as the number of moles in a liter. If the solution is `2.5M`, the molarity of the elements is the same basic amount, modified by the number of atoms of each element in the original compound.

In this case, we have one `Ca` atom and two `Cl` atoms in the compound. So, we will have `2.5M Ca^(+2)` and `2.5 xx 2 = 5M Cl^(-1)` ions in solution.