In a 2.5 M #CaCl_2# solution, what is the molarity of the calcium ions?

2 Answers
Sep 9, 2017

Answer:

AS the name says on the tin, the molarity of calcium ion is #2.5*mol*L^-1#....

Explanation:

And in one litre of solution there are #1*Lxx2.5*mol*L^-1xx6.022xx10^23*mol^-1# individual calcium ions.....What is the concentration of chloride ions?

Sep 9, 2017

Answer:

#2.5M#

Explanation:

Molarity is defined as the number of moles in a liter. If the solution is #2.5M#, the molarity of the elements is the same basic amount, modified by the number of atoms of each element in the original compound.

In this case, we have one #Ca# atom and two #Cl# atoms in the compound. So, we will have #2.5M Ca^(+2)# and #2.5 xx 2 = 5M Cl^(-1)# ions in solution.