In a curling match, a player slides a stone across the ice. If the coefficient of friction between the stone and the ice is 0.05, what initial speed should he give to the stone if it is to stop exactly 50 m away?
In a curling match, a player slides a stone across the ice. If the coefficient of friction between the stone and the ice is 0.05, what initial speed should he give to the stone if it is to stop exactly 50 m away?
In a curling match, a player slides a stone across the ice. If the coefficient of friction between the stone and the ice is 0.05, what initial speed should he give to the stone if it is to stop exactly 50 m away?
1 Answer
Mar 12, 2018
Let
Retarding force of friction
#F=muN=muMg#
where#N# is the normal reaction and#g=9.8\ ms^-2# is acceleration due to gravity.
Using Newton's Second Law of motion, Retardation due to this force
#r=(muMg)/M=0.05xx9.8=0.49\ ms^-2#
Using following kinematic expression to find initial velocity
#v^2-u^2=2as#
#0^2-u^2=2xx(-0.49)xx50#
#=>u^2=49#
#=>u=sqrt49=7\ ms^-1#
