Question

In a trapezium abcd ab //cd and ab is a diameter. Angle cab is 28 .Find the difference between angle adc and angle abc?

Answer 1

`ab` is the diameter
So semicircular`angle acb=90^@`

Given `anglecab=28^@`

So `angleabc=90^@-28^@=62^@`

Now `angle adc+angleabc=180^@`

So `angle adc=180^@-62^@=118^@`

So the difference between

`angle adc -angle abc=118^@-62^@=56^@`