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In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, what is the probability you will choose a consonant and then a vowel?

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Explanation

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Explanation:

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9
Sep 2, 2016

$\frac{21}{100}$

Explanation:

The numbers of vowels and consonants stay the same for the second tile, because the first tile was replaced.

The total number of tiles = 40.

$P \left(C , V\right) = P \left(C\right) \times P \left(V\right) \text{ ", larr" both must happen}$

= $\frac{28}{40} \times \frac{12}{40} = \frac{21}{100}$

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