# In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, what is the probability you will choose a consonant and then a vowel?

$\frac{21}{100}$

#### Explanation:

There are 40 tiles in total $\left(28 + 12 = 40\right)$

I can pick a consonant $\frac{28}{40} = \frac{7}{10}$ of the time.

I can pick a vowel $\frac{12}{40} = \frac{3}{10}$ of the time.

So to pick a consonant, replace the tile, then pick a vowel, the probability is:

$P \left(\text{consonant then vowel with replacement}\right) = \frac{7}{10} \times \frac{3}{10} = \frac{21}{100}$