# In graphing y=4(x-3)^2 -2, the vertex of the parabola is at what point?

May 6, 2016

Vertex$\to \left(x , y\right) \to \left(3 , - 2\right)$

#### Explanation:

Reading directly from the vertex form equation

${x}_{\text{vertex}} = \left(- 1\right) \times \left(- 3\right) = + 3$
${y}_{\text{vertex}} = - 2$

So Vertex$\to \left(x , y\right) \to \left(3 , - 2\right)$