Question

In how many different orders can six colored blocks be chosen from a set of 23 different blocks?

Answer 1

`72681840` Different orders

Explanation:

Given `n=23` and `r=6`

`nPr=(n!)/((n-r)!)`

`23P6=(23!)/((23-6)!)=(23!)/(17!)=(23*22*21*20*19*18*17!)/(17!)`

`23P6=(23*22*21*20*19*18*cancel17!)/(cancel17!)`

`23P6=72,681,840`

Have a nice day !from the Philippines..