# In lab you measure out 87.25 grams of C4H8O4 for an experiment. How many mol is this?

${\text{1.037mol}}_{{C}_{4} {H}_{8} {O}_{4}}$
1 mol ${C}_{4} {H}_{8} {O}_{4}$ = 84.12g
$87.25 {\text{g"_(C_4H_8O_4) * "1mol"_(C_4H_8O_4)/(84.12"g"_(C_4H_8O_4)) = "1.037mol}}_{{C}_{4} {H}_{8} {O}_{4}}$