Question

In parallel RC circuits, is it true that the larger the value of C, the larger the phase angle?

Answer 1

Yes.

Explanation:

The larger value of C, the smaller is its reactance Xc and the larger is the current Ic.

As the angle is = arctg (Ic/Ir),
the larger Ic the larger the angle.

Answer 2

Yes.

Explanation:

When an AC voltage having frequency `omega` is applied across a capacitor of capacity `C`, the impedance `Z_C` is given by

`Z_C=1/(jomega C)`, where `j-=sqrt -1` also

Capacitive Reactance `X_C -=(omegaC)^-1`

Now in a parallel `RC` circuit as shown in the figure

The total impedance is calculated by adding individual impedance in parallel.

`1/Z_(eq)=1/Z_R+1/Z_C=1/R+jomega C=1/R+j/(X_C)`
`implies Z_(eq)=(RX_C)/(X_C+jR)`

The phase angle between the applied voltage and total current is given by
`theta=tan^-1 (R/X_C)`
We observe that larger value of capacitor will lead to larger phase angle, `X_C` being in the denominator or `C` being in the numerator.