# In right triangle ABC, angle C is the right angle and angle B=30. What's the ratio of AC to BC?

$\frac{A C}{B C} = \frac{1}{\sqrt{3}}$
In $\triangle A B C , \angle C = {90}^{0} \mathmr{and} \angle B = {30}^{0} \mathmr{and}$,ratio of AC to BC is (AC)/(BC)=?
$\tan B = \frac{A C}{B C} = \tan {30}^{0} = \frac{1}{\sqrt{3}}$