# In the chemical equation  H_2 + Cl_2 ->2HCI , what are the mole ratios?

Sep 20, 2017

#### Answer:

Clearly the mole ratios of the reactants are $\text{1:1}$, and $\text{2 equiv}$ of product result.

#### Explanation:

And this can be seen from the stoichiometric equation you have already written.....alternatively we could write....

$\frac{1}{2} {H}_{2} \left(g\right) + \frac{1}{2} C {l}_{2} \left(g\right) \rightarrow H C l \left(g\right)$

....which preserves the same molar ratio, i.e. the SAME STOICHOMETRY. And thus we could say that 1 equiv of dihydrogen reacts with 1 equiv of dichlorine (and note that all of the reactive elemental gases are binuclear!) to gives the 2 equiv of hydrogen chloride gas.....

And likewise we could say that $1 \cdot g$ of dihydrogen combines with $35 \cdot g$ of dichlorine to give $36 \cdot g$ of hydrogen chloride gas. Stoichiometry is maintained: $\text{garbage in equal garbage out}$.