In the complete reaction of 22.99 g of sodium with 35,45 g of chloride, what mass of sodium chloride is formed?

1 Answer
Nov 19, 2015

Answer:

58.44 g

Explanation:

The reaction that takes place is:

Na + Cl -> NaCl
the ratio of this reaction is 1 : 1 : 1

Na = 22.9898 g/mole
Cl = 35.453 g/mole
NaCl = 58.44 g/mole

First you calculate the mole using the known data:
mole = mass / molar mass
mole sodium = 22.99 / 22.9898 = 1.00

since the ratio is 1 : 1 : 1, all you have to do is:
mass = mole * molar mass
mass NaCl = 1.00 * 58.44 = 58.44 g

you can check if all the mass of Cl is used by calculating the mass using the mole and the molar mass:
Mass Cl = 1.00 * 35.45 = 35.45 g
Which was the amount of mass used in the reaction so everything correct, meaning the amount of mass formed in the reaction is 58.44 grams.