# In the following equation, identify the x-intercepts in the graph y = 3x^2 + 19x – 40?

Jul 22, 2015

I found:
$x = - 8 , y = 0$
$x = \frac{5}{3} , y = 0$

#### Explanation:

You can set $y =$ and solve the equation:
$3 {x}^{2} + 19 x - 40 = 0$ using the Quadratic Formula to get:
${x}_{1 , 2} = \frac{- 19 \pm \sqrt{361 + 480}}{6} = \frac{- 19 \pm 29}{6}$
so you get two solutions:
${x}_{1} = - 8$
${x}_{2} = - \frac{10}{6} = \frac{5}{3}$