In the laboratory a student combines 39.3 mL of a 0.165 M manganese(II) chloride solution with 25.3 mL of a 0.328 M manganese(II) sulfate solution. What is the final concentration of manganese(II) cation ? M ?

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Answer 1 · 2018-03-06T04:44:03

The volumes are assumed to be additive...

#[Mn^(2+)]=(39.3xx10^-3*Lxx0.165*mol*L^-1+25.3xx10^-3*Lxx0.328*mol*L^-1)/((39.3*mL+25.3*mL)xx10^-3*L*mL^-1)#

#=0.229*mol*L^-1#

WE have used the defining quotient for concentration...

#"concentration"="moles of solute"/"volume of solution"#