Question

In the reaction `CH_3COOH + H_2O rightleftharpoons CH_3COO^(-) + H_2O`, what is a conjugate acid-base pair?

Answer 1

`CH_3COOH` and `CH_3COO^-`
`H_2O` and `H_3O^+`

Explanation:

So

the `CH_3COOH` is a acid

the `CH_3COOH` lost the hydrogen on the end so its the acid by the Bronsted Lowry Definition of acids

the `CH_3COO^-` is the conjugate base as in the reverse reaction, it would have to pick up `H^+` to form acetic acid again

The `H_2O` is an base (on the left), as it accepts the hydrogen ion that the acetic acid lost
(on the right side, it should be a `H_3O^+` instead)
The `H_3O^+` is a conjugate acid, as it would have to lose the `H^+` to revert to `H_2O`

:)