# In the reaction represented by the equation 2Al_2O_3 -> 4Al + 3O_2, what is the mole ratio of aluminum to oxygen?

$4 : 3$
As per the equation , $2$ moles of Aluminum Oxide ($A {l}_{2} {O}_{3}$) produces $4$ moles of Aluminum ($A l$) and $3$ moles of Oxygen (${O}_{2}$).
The ratio of $A l$ to $O$ is $\left(4 \text{ moles")/(3 " moles}\right)$ = $\frac{4}{3}$