Question

In the United States, 43% of people wear a seat belt while driving. If two people are chosen at random, what is the probability that both of them wear a seat belt?

Answer 1

If two occurrences are not related you multiply the chances

Explanation:

Chance of driver 1 wearing a seat belt =43% or `0.43`
For short I will write this as `P(d1)=0.43`
Then `P(d2)=0.43` (also)

Then both drivers wearing their seat belts can be written as: `P(d1)andP(d2)=P(d1)timesP(d2)`
(so AND becomes TIMES)

In numbers:
`P(d1)andP(d2)=0.43times0.43=0.1849~~18.5%`

Comment :
Only on the very low 43% score on seat belt usage. I hope this problem does not reflect current reality!