Index of refraction?

Light travels a distance of 0.941m in 4.01ns in a given substance.
What is the index of refraction of this substance?

1 Answer
Mar 18, 2018

I tried this:

Explanation:

We can evaluate the speed of light in this medium:
#"speed"=v="distance"/"time"#
#v=0.941/(4.01xx10^-9)=2.3xx10^8m/s#

the index of refraction can be written as:
#n=c/v#
representing the ratio between the speed in vacuum and the speed in a medium.

So we get:

#n=(3xx10^8)/(2.3xx10^8)=1.3#