Indicate in each case base, acid and conjugate pairs?

(HNO3+H2F2 --> H2No3+ + HF2-)
(HNO3+OH- --> NO3- + H2O)
(HBr+HCL --> Br- + H2CL+)
(HSO3- + H2O --> SO3-2 + H3O+)
(NH4+ + CO3-2 --> HCL3- + NH3)????

1 Answer
Truong-Son N.
Feb 7, 2018

You're just looking for a difference of one #"H"^(+)#... but some of these don't make physical sense.

I don't know who made these questions up, but some of these are highly theoretical and I'll only answer the ones that make actual sense.

This one is hard to believe:

#color(red)(overbrace("HNO"_3(aq))^"''base''" + overbrace("H"_2"F"_2(aq))^"this acid exists" -> overbrace("H"_2"NO"_3^(+)(aq))^"conjugate acid..." + overbrace("HF"_2^(-)(aq))^"conjugate base")#

This one is normal:

#overbrace("HNO"_3(aq))^"acid" + overbrace("OH"^(-)(aq))^"base" -> overbrace("NO"_3^(-)(aq))^"conjugate base" + overbrace("H"_2"O")^"conjugate acid"#

This one is actually possible since #"HBr"# is a stronger acid by a factor of #100#...

#overbrace("HBr")^"acid" + overbrace("HCl")^"''base''" -> overbrace("Br"^(-)(aq))^"conjugate base" + overbrace("H"_2"Cl"^(+)(aq))^"conjugate acid"#

This one is an equilibrium, not a simple forward reaction.

#overbrace("HSO"_3^(-)(aq))^"acid" + overbrace("H"_2"O"(l))^"base" rightleftharpoons overbrace("SO"_3^(2-)(aq))^"conjugate base" + overbrace("H"_3"O"^(+)(aq))^"conjugate acid"#

This one is another equilibrium:

#overbrace("NH"_4^(+)(aq))^"acid" + overbrace("CO"_3^(2-)(aq))^"base" rightleftharpoons overbrace("HCO"_3^(-)(aq))^"conjugate acid" + overbrace("NH"_3(aq))^"conjugate base"#

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