Integral(cosx-secx)?

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Answer 1 · 2018-05-01T16:35:11

#I=sinx-ln|secx+tanx|+c#

This is your first question .

Your question is : integral(cosx-secx).

You have selected "Trigonometry-section."

But the word "Integral" is related to calculus.

So,I think your question is:

#I=int(cosx-secx)dx#

#I=sinx-ln|secx+tanx|+c#

Note:
#cosx-secx=cosx-1/cosx=(cos^2x-1)/cosx=-(1-cos^2x)/cosx#
#=-sin^2x/cosx#
I hope your next question will be "meaningful".