Integral With absolute value how to solve it?
(Its a little bit hard to see, but the limits are 0 and 2)
(Its a little bit hard to see, but the limits are 0 and 2)
1 Answer
Mar 15, 2018
Please see below.
Explanation:
For
So,
# = int_0^a (-x^2+ax) dx + int_a^2 (x^2-ax) dx#
To find
After finding