# Iron rusts according to the following reaction: #4Fe (s) + 3O_2 (g) + 4H_2O -> 2Fe_2O_3(H_2O)_2#. If 1.4 liters of oxygen were added to excess water and iron at a pressure of 0.97 atms and a temperature of 55 C, how many grams of iron would rust?

##### 1 Answer

Your equation is unbalanced....

#### Explanation:

Let us readdress it....iron metal is oxidized to

Dioxygen is reduced to water...

And

…. and we cancel to give...

And note that this equation assumes COMPLETE oxidation....iron oxide chemistry, i.e. rust chemistry is a very broad church...and many iron oxides and hydrous oxides are known. And so we calculate the moles of dioxygen gas....and plug this value back into the given equation....