The formula of #"2-methylpentane"-=C_6H_14#...i.e. NO DEGREES of UNSATURATION.... The formula falls under the class #C_nH_(2n+2)#... #"2-methylpentane"# is thus a saturated molecule, with NEITHER double bonds, NOR ring junctions...
The standard alcohols, #"ethyl alcohol"#, #"methyl alcohol"#, #"isopropyl alcohol"#, are also SATURATED by this criterion.