Is #f(x) =(2x+8)^3/(x^2/3+1)# concave or convex at #x=-4#?
1 Answer
Apr 4, 2018
Below
Explanation:
For stationary points,
ie
Since you are finding
You can use a table
when
Therefore, the point at x=-4 is neither concave up nor concave down. Instead at x=4, you will have something that looks like this cubic graph at x=0
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- (i don't remember its name so I had to give you an example instead)
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graph{x^3 [-10, 10, -5, 5]}