Is #f(x)=3x^-2 -3# a function?

1 Answer
Mar 7, 2018

We can rewrite #f(x)# as #f(x)=3/x^2-3#. For this equation to be a function, one value of #x# must not give more than one value for #y#, so each #x# value has a unique #y# value. Also, every value for #x# must have a value for #y#.

In this case, each value for #x# has one value for #y#. However, #x!=0# since #f(0)=3/0-3="undefined"#.

So, #f(x)# is not a function.

However, it can be made a function by applying limits or ranges of #x# values, in this case it is a function if #f(x)=3x^-2-3,x!=0#.